the `names` function is indeed the right way to go about it: julia> un = Union(Int, Float64) Union(Int64,Float64)
julia> names(un) 1-element Array{Symbol,1}: :types julia> un.types (Int64,Float64) julia> un.types[1] Int64 julia> un.types[2] Float64 For datatypes: julia> type A a::Int b::Float64 end julia> names(DataType) 14-element Array{Symbol,1}: :fptr :env :code :name :super :parameters :names :types :ctor_factory :instance :size :abstract :mutable :pointerfree julia> A.types (Int64,Float64) Also have a look at this excellent post: http://blog.leahhanson.us/julia-helps.html On Fri, 2014-05-16 at 08:09, tony.hf.f...@gmail.com wrote: > Hello, new user and subscriber here. Is there a way to decompose a > UnionType back into its constituent type(s)? > > I tried names(): > >> dt = Union(Int,Float64) >> names(dt) > 1-element Array{Symbol,1}: > :types > > convert() seems to hit dead-ends. > > Help appreciated. > > Tony --