There are improvements planned, which should make it possible to write the 
code as you originally wrote. For now though, you will have to write it C 
style if you want the highest performance.

-viral

On Monday, May 26, 2014 12:00:50 AM UTC+5:30, Christoph Ortner wrote:
>
>
> Thank you both for the suggestions. I've re-written the code >> JULIA3, with 
> amazing results. JULIA2 was the previous "optimised" code.
>>
>>
> Test 1, J2: 0.751340928, J3: 0.008927998, C: 0.007420171; max-error = 0.0
>
> Test 2, J2: 0.71344446, J3: 0.009042345, C: 0.007583811; max-error = 0.0
>
> Test 3, J2: 0.719000046, J3: 0.008970343, C: 0.007626061; max-error = 0.0
>
> Test 4, J2: 0.707967183, J3: 0.008979525, C: 0.007572056; max-error = 0.0
>
> Test 5, J2: 0.730254977, J3: 0.009012892, C: 0.007649305; max-error = 0.0
>
> . . ..   (repeating the test gives consistent results; C is gcc with -O3)
>
> The new code and the test-code are copied below. Of course this means I 
> have to write C-style codes in Julia to get this sort of performance. Why 
> does Julia not optimise 
>
>         dE[:, k] += dJ
>
>         dE[:, n] -= dJ
>
> to
>
>         for i = 1:d
>
>             dE[i, k] += dJ * r[i]
>
>             dE[i, n] -= dJ * r[i]
>
>         end
>
> ?
>
>
> > I think you should also replace your (s*s*s*s*s) with s^5 - it'll 
> > automatically do the "right thing", and I'd be surprised if that is slower.
>
> If I revert to s^5, etc, then I lose 2 orders of magnitude.
>
>
> I will look into NumericExtensions and the profiler next.
>
>
> Thank you again for the help.
>
>    Christoph
>
>
>
> function energy_julia3(x)
>
> N = size(x,2); d = size(x,1)
>
> E = 0.0; dE = zeros(d, N)
>
> r = zeros(d);
>
> dJ = 0.; s = 0.
>
> for n = 1:(N-1)
>
>     for k = (n+1):N
>
>         s = 0.
>
>         for i = 1:d
>
>             r[i] = x[i,k]-x[i,n]
>
>             s += r[i]*r[i]
>
>         end
>
>         E += 1./(s*s*s*s*s*s) - 2. / (s*s*s)
>
>         dJ = -12. * (1./(s*s*s*s*s*s*s) - 1./(s*s*s*s))
>
>         for i = 1:d
>
>             dE[i, k] += dJ * r[i]
>
>             dE[i, n] -= dJ * r[i]
>
>         end
>
>     end
>
> end
>
> return E, dE
>
> end
>
>
> function meshgrid{T}(vx::AbstractVector{T}, vy::AbstractVector{T})
>
>     m, n = length(vy), length(vx)
>
>     vx = reshape(vx, 1, n)
>
>     vy = reshape(vy, m, 1)
>
>     (repmat(vx, m, 1), repmat(vy, 1, n))
>
> end
>
>
> function lj_test_juliaopt(N)
>
>     x = linspace(0, N, N+1)   
>     x, y = meshgrid(x, x)
>
>     x = [x[:] y[:]]'
>
>    for n = 1:10
>
>        tic(); Ej2, dEj2 = energy_julia2(x); t2 = toq();
>
>        tic(); Ej3, dEj3 = energy_julia3(x); t3 = toq();
>
>        tic();
>
>        dEc = zeros(size(x))
>
>        Ec = ccall( (:energy, "./libljtest_c"), Cdouble, (Ptr{Cdouble}, 
> Ptr{Cdouble}, Cint, Cint), x, dEc, size(x,2), size(x,1))
>
>        tc = toq();
>
>        error = max( abs(Ej2-Ej3), abs(Ej2-Ec), norm(dEj2[:]-dEj3[:], Inf), 
> norm(dEj2[:]-dEc[:], Inf) )
>
>        println("Test ", n, ", J2: ", t2, ", J3: ", t3, ", C: ", tc, "; 
> max-error = ", error)
>
>     end
>
> end
>
>

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