sqrt(x.^2 .+ y.^2) .< radius
is a vector of booleans
?:
expects a boolean
you probably want something like:
inside_disc(x,y,radius) = map(good -> good ? 1 : 0, sqrt(x.^2+y.^2).<radius)
On Friday, June 6, 2014 10:18:36 PM UTC-4, Zahirul ALAM wrote:
>
> When I pass two arrays the function returns:
>
> type: non-boolean (BitArray{1}) used in boolean context while loading In[10],
> in expression starting on line 1
>
>
> I have modified the function to address the element wise operation as follows:
>
>
> inside_disc(x,y,radius) = sqrt(x.^2 .+ y.^2) .< radius ? 1 : 0
>
> seems to me that the error is being thrown by .< operation. What am I
> missing?
>
>
> On Friday, 6 June 2014 20:34:22 UTC-4, Miguel Bazdresch wrote:
>>
>> I'm not sure I understand the question. Do you mean something like this?
>>
>> inside_disc(x,y,radius) = sqrt(x^2+y^2)<radius ? 1 : 0
>>
>> -- mb
>>
>>
>> On Fri, Jun 6, 2014 at 8:28 PM, Zahirul ALAM <[email protected]> wrote:
>>
>>> I guess one can do a for loop. But how do I vectorize the code?
>>>
>>>
>>> On Friday, 6 June 2014 20:27:46 UTC-4, Zahirul ALAM wrote:
>>>>
>>>> How would one implement a step function like behaviour in julia? In
>>>> mathematica one can write the following to create a circle with value of 1
>>>> within the radius and 0 outside
>>>>
>>>> UnitBox[Sqrt[X^2 + Y^2]*0.5/radius];
>>>>
>>>> X and Y are the coordinates.
>>>>
>>>
>>
