If you mean replace a by 1 in the expression, you can do it as follows:
julia> e = :(typeof(a) <: Real && typeof(b) <: Real)
:(typeof(a) <: Real && typeof(b) <: Real)
julia> dump(e, 10) # look at the structure of e
Expr
head: Symbol &&
args: Array(Any,(2,))
1: Expr
head: Symbol comparison
args: Array(Any,(3,))
1: Expr
head: Symbol call
args: Array(Any,(2,))
1: Symbol typeof
2: Symbol a
typ: Any
2: Symbol <:
3: Symbol Real
typ: Any
2: Expr
head: Symbol comparison
args: Array(Any,(3,))
1: Expr
head: Symbol call
args: Array(Any,(2,))
1: Symbol typeof
2: Symbol b
typ: Any
2: Symbol <:
3: Symbol Real
typ: Any
typ: Any
julia> e.args[1].args[1].args[2]
:a
julia> e.args[1].args[1].args[2] = 1
1
julia> e
:(typeof(1) <: Real && typeof(b) <: Real)
On Tue, Jun 10, 2014 at 3:37 PM, Gustavo Lacerda
<[email protected]> wrote:
> hi,
>
> julia> parse("typeof(a)<:Real&&typeof(b)<:Real")
> :(typeof(a) <: Real && typeof(b) <: Real)
>
> I would like to substitute 'a' for 1 in this Expr. Any suggestions?
>
> Gustavo
>
>
> --
> Gustavo Lacerda
> http://www.optimizelife.com