hum, good point.
however, the same applies if I change this:
type Myt{ T<:Real}
n :: Int64
chain :: Array{T,1}
function Myt(n,z::T)
x = [z for i=1:n]
new(n,x)
end
end
or is that not what you meant? I basically want to fill array "chain" with
several copies of type T.
On Wednesday, 11 June 2014 16:13:47 UTC+1, John Myles White wrote:
>
> Your type’s definition doesn’t seem to depend upon T in any way. Keep in
> mind that the type is really just the first two lines of your code:
>
> type Myt{T <: Real}
> n::Int64
> chain::Array
> end
>
> The constructor isn’t part of the type itself, so the dependency on T
> needs to occur in the type.
>
> — John
>
> On Jun 11, 2014, at 8:04 AM, Florian Oswald <[email protected]
> <javascript:>> wrote:
>
> Hi,
>
> I'm trying to understand why this is not working:
>
> type Myt{ T<:Real}
> n :: Int64
> chain :: Array
> function Myt(n,z::T)
> x = [z for i=1:n]
> new(n,x)
> end
> end
>
> i get the error
> julia> Myt(10,18.0)
> ERROR: no method Myt{T<:Real}(Int64, Float64)
>
> I thought that was very similar to the point example on the manual?
>
> type Point{T<:Real}
> x::T
> y::T
>
> Point(x::T, y::T) = new(x,y)end
>
>
> thanks
>
>
>