Big thx, it work,
Paul
W dniu 2014-06-16 21:24, Dahua Lin pisze:
|u =trues(length(x))
u[[5,7]]=false
ir =0
vr =-Inf
fori =1:length(x)
ifu[i]&&x[i]>vr
        ir =i
        vr =x[i]
end
end
|

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