Thanks. Didn't know about that syntax. Now with it, I might prefer the
following as Array{String,1} is exactly what I want.
julia> dts1 = convert(Array{String,1},dt)
3-element Array{String,1}:
"2010/1/4T15:00:00"
"2010/1/5T15:00:00"
"2010/1/6T15:00:00"
On 2014年07月25日 10:40, Miles Lubin wrote:
How about "convert(Vector{String},dt)"?
On Thursday, July 24, 2014 8:39:02 PM UTC-6, K leo wrote:
I have an Array{Any,1}, but I want to convert to Array{String,1}. The
only way I know is through comprehension.
julia> dt
3-element Array{Any,1}:
"2010/1/4T15:00:00"
"2010/1/5T15:00:00"
"2010/1/6T15:00:00"
julia> dts = [convert(String, dt[i]) for i=1:length(dt)]
3-element Array{String,1}:
"2010/1/4T15:00:00"
"2010/1/5T15:00:00"
"2010/1/6T15:00:00"
