Doesn't map choose the tightest possible type nowadays? So maybe just map the identity?
On Sun, Jul 27, 2014 at 4:03 PM, Ivar Nesje <[email protected]> wrote: > But it does use promotion, so it might not be what you are looking for. > > kl. 22:02:52 UTC+2 søndag 27. juli 2014 skrev Ivar Nesje følgende: >> >> This works somewhat like what you ask: >> >> vcat({1,0.1}...) >> >> Ivar >> >> kl. 21:42:24 UTC+2 søndag 27. juli 2014 skrev John Myles White følgende: >>> >>> Do we have a function that will take in an Array{Any}, compute the >>> typejoin of its elements and convert the Array to the tightest possible >>> type? >>> >>> — John >>> >
