Your problem is with the first index (`i == 1`). You can't check if the
previous element is < 0. You could adjust your range (the
`1:length(outputarray)`) to only run through elements for which your
if-condition makes sense.

-- Leah


On Wed, Jul 30, 2014 at 5:12 PM, <[email protected]> wrote:

> I'm a bit stuck on this one. Could I get one more hint about a way I could
> get the same thing done without using the illegal indexing?
>
> On Wednesday, July 30, 2014 5:46:58 PM UTC-4, John Myles White wrote:
>
>> Yeah, it’s the combination of (a) the use of i and i+1 indexing with (b)
>> the use of a loop that goes from i = 1 to i = length(outputarray).
>>
>>  — John
>>
>>
>> On Jul 30, 2014, at 2:44 PM, [email protected] wrote:
>>
>> To correct the bug, is it this?
>>
>> if outputarray[i] < 0 && outputarray[i+1] >= 0
>>             count += 1
>>         end
>>
>> Factoring in that Julia begins indexing from 1.
>>
>> On Wednesday, July 30, 2014 4:41:43 PM UTC-4, John Myles White wrote:
>>>
>>> This pseudocode almost works. Just replace Int64[1:len(outputarray)]
>>> with 1:length(outputarray).
>>>
>>> There’s also a bug in your core logic, but I’ll leave fixing that as an
>>> exercise to the reader.
>>>
>>>  — John
>>>
>>> On Jul 30, 2014, at 1:03 PM, [email protected] wrote:
>>>
>>> Hi guys,
>>>
>>> I asked this in a previous thread, but because that diverged off-topic
>>> from my existing question, I decided to create a new thread.
>>>
>>> Anyhow, say I have an array
>>>
>>> outputarray = Float64[-1.23423,-3.23423,-2.34234,-2.12342,1.23234,2.
>>> 23423,-2.23432,5.2341,0.01111,1.23423]
>>>
>>> This array lists the output of some function. I want to count the number
>>> of times that the function passes by or equals 0 while emerging from a
>>> negative f(x).
>>>
>>> In pseudocode, I want to do:
>>>
>>> function counter(outputarray)
>>>     count = 0
>>>     for i in Int64[1:len(outputarray)]
>>>         if outputarray[i] >= 0 && outputarray[i-1] < 0
>>>             count += 1
>>>         end
>>>     end
>>>     return count
>>> end
>>>
>>> What would be the most efficient way of doing this in Julia?
>>>
>>> Thanks,
>>> Wally
>>>
>>>
>>>
>>

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