thank you
On Monday, 11 August 2014 09:42:07 UTC-4, j verzani wrote:
>
> The SymPy package adds / for PyObjects and other functions so that working
> with SymPy is a bit easier that going through PyCall directly. The package
> needed a besselj function though. One is added now, output below. The
> problem is that the sympy functions are not generated programmatically,
> rather added by hand one by one.
>
> julia> using SymPy
>
> julia> r= Sym("r")
>
> julia> limit(besselj(1, r)/r, r, 0)
>
> 1/2
>
>
> On Monday, August 11, 2014 4:37:49 AM UTC-4, Hans W Borchers wrote:
>>
>> As far as I see, Sympy *does* know the limit at 0.0:
>>
>> >>> from sympy import *
>> >>> x = symbols('x')
>> >>> limit(besselj(1, x)/x, x, 0)
>> 1/2
>>
>> If in Julia you call it like limit(besselj(1, x)/x, x, 0), then Julia
>> assumes it to be its own function, not SymPy's.
>>
>> If on the other hand you call all SymPy functions fully expanded:
>>
>> julia> using PyCall
>>
>> julia> @pyimport sympy
>>
>> julia> x = sympy.symbols("x")
>>
>> julia> sympy.limit(sympy.besselj(1, x)/x, x, 0.0)
>> `/` has no method matching /(::PyObject, ::PyObject)
>>
>> So the problem seems to be with how PyCall interprets this expression
>> before sending it to SymPy.
>>
>>
>> On Monday, August 11, 2014 5:55:56 AM UTC+2, Zahirul ALAM wrote:
>>>
>>> Is there way of calculating limit of a function?
>>>
>>> I have tried SymPy Package. But it unfortunately doesnot compute limit
>>> for bessel function.
>>>
>>> r= Sym("r")
>>> limit(besselj(1, r)/r, r, 0)
>>>
>>> returns the following error:
>>>
>>> `besselj` has no method matching besselj(::Int64, ::Sym)
>>> while loading In[27], in expression starting on line 1
>>>
>>>
>>> the it works for cosine, sine,
>>> r= Sym("r")
>>> limit(sin( r)/r, r, 0)
>>>
>>> Any idea? is there a built an undocumented Julia function which can
>>> calculate limit?
>>>
>>>
>>>
>>>
