One solution is to use the @sprintf macro, i.e. something like
@sprintf("cons_%f, 0.00001).
Med venlig hilsen
Andreas Noack
2014-08-13 7:42 GMT-04:00 Charles Novaes de Santana <
[email protected]>:
> Dear all,
>
> I would like to convert a float variable with more than 5 decimal digits
> to a string, but in the literal notation, not in the "logarithmic" one.
>
> For example, if I do:
>
> floatvar = 0.00001;
> charvar = string("cost_",floatvar);
> println(charvar);
>
> charvar is written as: "cost_1.0e-5". Instead of that, I would like to get
> "cost_0.00001".
>
> Any idea about how to do that? I am sorry for this very basic question,
> but so far I couldn't realize by myself neither find in the forums a way to
> do that.
>
> Thank you for your attention and for any help!
>
> Best,
>
> Charles
>
>
> --
> Um axé! :)
>
> --
> Charles Novaes de Santana, PhD
> http://www.imedea.uib-csic.es/~charles
>
