Hello!
I'm trying to define a function using a macro. But I just dont get it. Look
at the following Examples:
Using default arguments, everything works as expected:
macro myDef2(name)
return esc(:( $name(x, y=3) = x*y ))
end
@myDef2 f2
f2(4) # gives 12, as expected
f2(4, 5) #gives 20, as expected
So, I assumed the same would work for keyword arguments, but it doesn't:
macro myDef3(name)
return esc(:( $name(x; y=3) = x*y ))
end
@myDef3 f3
f3(4) # gives 3 but 12 expected
f3(4, y=5) #gives 5 but 20 expected
Even more strange:
macro myDef4(name)
return esc(:( $name(x; y=3) = x )) # not using y here!
end
@myDef4 f4 # gives ERROR: syntax: malformed expression
Am I doing something wrong or is this a bug?
Maybe I just don't understand what esc() does or how to define functions in
macros, I'm new to Julia.
I'm using Version 0.3.0 (2014-08-20 20:43 UTC).
- Jonas
