The Expr method had an error and would overwrite the expressions in its
argument. Here's a better version.
function biggen(x::Expr)
Meta.isexpr(x, :call) || error("Only works for calls right now")
y = copy(x);
for i in 2:length(y.args)
y.args[i] = biggen(x.args[i])
end
return y
end
(sorry about the repost... I'm going to give myself an email timeout right
now.)
On Friday, September 19, 2014 9:57:00 AM UTC-5, Gray Calhoun wrote:
>
>
>
> On Friday, September 19, 2014 9:32:09 AM UTC-5, David P. Sanders wrote:
>>
>> El viernes, 19 de septiembre de 2014 09:26:09 UTC-5, David P. Sanders
>> escribió:
>>>
>>> El viernes, 19 de septiembre de 2014 08:58:56 UTC-5, Isaiah escribió:
>>>>
>>>> To do what you want, very briefly:
>>>>
>>>> > x.args[3] == :pi && x.args[3] = Expr(:call, :BigFloat, :pi)
>>>> ...
>>>>
>>> Yes, that's what I need, thanks. Now I need to iterate over the (in
>>> principle arbitrarily complex, i.e. nested) syntax tree and do this
>>> everywhere.
>>> Is there a standard method for this kind of iteration?
>>>
>>
>> I guess some kind of recursion. I'll give it a go...
>>
>
> This might help you get started:
>
> biggen(x::Symbol) = Expr(:call, :big, x)
> [...cut...]
>
