"optionally *along dimensions in region*" (emphasis mine). You are attempting to read along the tenth dimension of the array.
You're trying to split the array into groups of ten elements, it sounds like. [std(A[10(n-1)+1:10n]) for n in 1:length(A)./10] On Thursday, October 9, 2014 5:56:01 PM UTC-5, K leo wrote: > > I am hoping to get the std's of every 10 consecutive elements in A. > > std(v[, region]) > Compute the sample standard deviation of a vector or array v, optionally > along dimensions in region. The algorithm returns an estimator of the > generative distribution’s standard deviation under the assumption that > each entry of v is an IID drawn from that generative distribution. This > computation is equivalent to calculating sqrt(sum((v - mean(v)).^2) / > (length(v) - 1)). Note: Julia does not ignore NaN values in the > computation. For applications requiring the handling of missing data, > the DataArray package is recommended. > > On 2014年10月10日 06:49, Patrick O'Leary wrote: > > On Thursday, October 9, 2014 5:42:40 PM UTC-5, K leo wrote: > > > > julia> std(A, 10) > > > > > > A only has elements along the first dimension. What behavior do you > > expect here? > >
