Also, the following runs but still returns a Vector{Any}. How is this
possible?
function makestring(fun)
A::Array{ASCIIString} = [fun(i) for i = 1:3]
end
On Wednesday, October 29, 2014 1:45:51 PM UTC-4, Zenna Tavares wrote:
>
> As shown in the following example, I am getting differently typed arrays
> depending on where I use the list comprehension.
>
> f(i) = "$i"
> A = [f(i) for i = 1:3]
> function makestring(fun)
> A = [fun(i) for i = 1:3]
> end
> B = makestring(f)
>
> In this example A has type Vector{ASCIIString} while B has type
> Vector{Any}. What gives? And is there a workaround such that we get a more
> specific type?
>
> I understand there are some open issues related to this, but I am not sure
> if this case comes under what's already been discussed.
>
>
>
