julia> 2*10.97 + 23.9985
45.938500000000005
julia> 2*10.97 + 23.9985 == 45.938500000000005
true
Amazing. I never expected this. Is floating point comparison going to
be guaranteed?
On 2014年11月05日 08:48, Stefan Karpinski wrote:
Some systems round their answers as John said but it's easy to check
that it's a lie:
R version 3.1.0 (2014-04-10) -- "Spring Dance"
> 2*10.97 + 23.9985
[1] 45.9385
> 2*10.97 + 23.9985 == 45.9385
[1] FALSE
This is perl 5, version 16, subversion 2 (v5.16.2)
DB<1> x 2*10.97 + 23.9985
0 45.9385
DB<2> x 2*10.97 + 23.9985 == 45.9385
0 ''
I don't have a working copy of Matlab right now, but I think it does
this too.
On Tue, Nov 4, 2014 at 8:31 PM, Neil Devadasan <[email protected]
<mailto:[email protected]>> wrote:
Thanks
On Tuesday, November 4, 2014 2:13:37 PM UTC-5, John Myles White
wrote:
Hi Neil,
Julie does math the same way that all computers do math.
You're probably coming from another language where a lot of
effort is invested into pretending that computers offer a
closer approximation to abstract mathematics than they
actually do. Those systems have been lying to you.
Put another way: you just took the red pill by using Julia.
-- John
On Nov 4, 2014, at 11:06 AM, Neil Devadasan
<[email protected]> wrote:
> julia> f(x::Float64, y::Float64) = 2x + y;
>
> julia> f(10.97,23.9985)
> 45.938500000000005
>
> The above method execution of function f returns an answer
that I cannot understand. Can someone clarify?
>
> Thank you.
