wow this works perfectly, thanks you very much!
El viernes, 14 de noviembre de 2014 00:58:02 UTC+9, David Smith escribió:
>
> In case this helps, I wrote my own imshow() function a while back that
> copied spy() but took varargs and had more customizations explicitly
> included. It might fix the label problems or at least give you inspiration.
>
>
> function imshow(x, title::String="", units::String="", args...)
> is, js, values = findnz(x)
> m, n = size(x)
> df = DataFrames.DataFrame(i=is, j=js, value=values)
> plot(df, x="j", y="i", color="value",
> Coord.cartesian(yflip=true, fixed=true)
> , Scale.x_continuous(minvalue=0.5, maxvalue=n+0.5)
> , Scale.y_continuous(minvalue=0.5, maxvalue=m+0.5)
> , Geom.rectbin, Stat.identity
> , Guide.title(title) , Guide.colorkey(units)
> , Guide.XLabel(""), Guide.YLabel("")
> , Guide.xticks(ticks=[1,n]), Guide.yticks(ticks=[1,m])
> , Theme(panel_fill=color("black"), grid_line_width = 0inch)
> , args...)
> end
>
> On Thursday, November 13, 2014 9:09:37 AM UTC-6, Eduardo Lenz wrote:
>>
>>
>> Is there an equivalent in Winston ?
>>
>> Thanks.
>>
>>
>> On Thursday, February 13, 2014 10:47:50 PM UTC-2, Daniel Jones wrote:
>>>
>>> There's actually a special function "spy" to make plotting matrices
>>> simpler, where spy(M) returns a plot. All that function does is basically
>>> call findnz on the matrix and pass the result to x, y, and color in the
>>> regular plot function.
>>>
>>> Special handling of matrix arguments is something to consider though.
>>>
>>> On Thursday, February 13, 2014 4:38:16 PM UTC-8, Elliot Saba wrote:
>>>>
>>>> Hey there, I'm trying to use Gadfly's Geom.binrect to plot a matrix,
>>>> but I can't figure out how to do it without going through a lot of
>>>> rigamarole to generate a DataFrame like is used in the example
>>>> <https://github.com/dcjones/Gadfly.jl/blob/master/doc/geom_rectbin.md>
>>>> docs.
>>>>
>>>> I have, say, a 10x10 matrix:
>>>>
>>>> z = randn(10,10)
>>>>
>>>> In matlab, if I wanted to plot it, I would just imagesc(z). I know
>>>> that if I had a dataframe with a row for each point in z stored in a
>>>> column, and the x/y coordinates recorded in their own columns, I could
>>>> coerce Gadfly to plot what I want as shown in the example. But is there a
>>>> simpler way to do this? I've tried something like:
>>>>
>>>> plot(x=1:10, y=1:10, color=z, Geom.rectbin)
>>>>
>>>> But Gadfly just plots one pixel for each x and y passed in. I
>>>> understand why it's doing that, I just don't know the easiest way to get
>>>> it
>>>> to treat z as a matrix, instead of a vector.
>>>>
>>>> Thanks,
>>>> -E
>>>>
>>>
