X[:, 3] doesn't produce a SubArray. It produces a brand new array. -- John
On Nov 21, 2014, at 10:30 AM, Ján Dolinský <[email protected]> wrote: > Hello, > > I wanted an inplace function to write a result into a subarray as follows: > > X = zeros(10,5) > fill!(X[:,3], 0.1) > > The X[:,3] is however not updated. > > X[:,3] = fill(0.1, 10) does the update as expected. > > Is this a desired behaviour ? > > > --- > > Alternatively, I can do > > r = view(X,:,3) > fill!(r, 0.1) > > This results in an updated column of X > > I wonder which is likely to be more efficient if used in a loop: > > X[:,3] = fill(0.1, 10) > > or > r = view(X,:,3) > fill!(r, 0.1) > > > Thanks, > Jan
