Works for me. --Tim
On Monday, December 01, 2014 06:43:57 PM Pileas wrote: > Tim, > > this code for example (which is in the description of the package): > > # ------------------------------------------------------- > using Grid > c = 2.3 # center > a = 8.1 # quadratic coefficient > o = 1.6 # vertical offset > qfunc = x -> a*(x-c).^2 + o > xg = Float64[1:5] > y = qfunc(xg) > yi = InterpGrid(y, BCnil, InterpQuadratic) > # ----------------------------------------------------------------------- > > gave this error: ERROR: InterpGrid not defined. > > Τη Δευτέρα, 1 Δεκεμβρίου 2014 9:26:28 μ.μ. UTC-5, ο χρήστης Tim Holy έγραψε: > > On Monday, December 01, 2014 06:22:28 PM Pileas wrote: > > > Matlab has built-in functions like interp, interp1, spline etc. to do > > > interpolation. > > > > > > Does Julia have any built-in functions that can do the same job? > > > > > > P.S.1 The "Grid" package does not work in Julia 0.3.3 > > > > Ummm, PackageEval (http://iainnz.github.io/packages.julialang.org/) is > > showing > > green for Grid on Julia 0.3.3. Specifically what problem are you having > > with > > it? > > > > --Tim
