Hi folks, I have the following code fragment:
x=1 let x=2 println(x) # Line 1 exp=:(x+1) println(eval(exp)) # Line 2 end It contains two variables both named x, one inside the scope defined by let, and one at global scope. If I run this code the output is: 2 2 This indicates that (i) that line 1 is using the local version of x, and (ii) that line 2 is using the global version of x. If I remove this global x I now get an error because eval() is looking for the global x which no longer exists: let x=2 println(x) # Line 1 exp=:(x+1) println(eval(exp)) # Line 2 end 2 ERROR: x not defined My question: when evaluating an expression using eval() such as line 2, how can I force Julia to use the local (not global) version of x and thus avoid this error? Thanks Mike
