You can also work directly with the HDF5 file as an array object...
using HDF5
hfi=h5open("myfile.h5","w"); # create the file
close(hfi)
A = reshape(1: 120, 15, 8);
hfi = h5open("myfile.h5","r+") # read/write access
hfi["mygroup/A"] = A
15x8 Array{Int64,2}:
1 16 31 46 61 76 91 106
...
14 29 44 59 74 89 104 119
15 30 45 60 75 90 105 120
data = hfi["mygroup/A"][2:3:15,3:5]
5x3 Array{Int64,2}:
32 47 62
35 50 65
38 53 68
41 56 71
44 59 74
hfi["mygroup/A"][2:3,3:5]
2x3 Array{Int64,2}:
32 47 62
33 48 63
hfi["mygroup/A"][2:3,3:5]=[-1 -2 -3; -4 -5 -6]
2x3 Array{Int64,2}:
-1 -2 -3
-4 -5 -6
hfi["mygroup/A"][1:5,:]
5x8 Array{Int64,2}:
1 16 31 46 61 76 91 106
2 17 -1 -2 -3 77 92 107
3 18 -4 -5 -6 78 93 108
4 19 34 49 64 79 94 109
5 20 35 50 65 80 95 110
foo = hfi["mygroup/A"]
HDF5 dataset: /mygroup/A (file: myfile.h5)
foo[1:5,:]
5x8 Array{Int64,2}:
1 16 31 46 61 76 91 106
2 17 -1 -2 -3 77 92 107
3 18 -4 -5 -6 78 93 108
4 19 34 49 64 79 94 109
5 20 35 50 65 80 95 110
close(hfi)
HDF5 is awesome!
On Sun, Jan 4, 2015 at 4:59 PM, paul analyst <[email protected]> wrote:
> Of course, first I read :)
> Is there about reading range array. I need to save a range of In analogy
> to.
>
> A = reshape (1: 120, 15, 8)
> h5write ("/ tmp / test2.h5", "mygroup2 / A", A)
> data = h5read ("/ tmp / test2.h5", "mygroup2 / A" (2: 3: 15: 3: 5))
>
> Paul
>
>
> W dniu niedziela, 4 stycznia 2015 14:14:03 UTC+1 użytkownik Tim Holy
> napisał:
>>
>> If I understand correctly, then yes, that's possible. See the HDF5 docs.
>>
>> --Tim
>>
>> On Sunday, January 04, 2015 04:25:13 AM paul analyst wrote:
>> > How to overwrite to an existing file, only range of data?
>> > In HDF5 can do this?
>> > I have an array of zeros 10 x 10
>> > I need an existing file owerwrite range rand (5x5), for example.
>> > Existingfile [2: 7.3: 8]
>> > Paul
>>
>>
