Sure. Here's how I remind myself how to do this: julia> using Grid
julia> @edit show(STDOUT, InterpGrid) # OK, I see that it prints InterpGrid.name julia> @which show(STDOUT, InterpGrid.name) show(io::IO,tn::TypeName) at show.jl:107 # Aha! julia> print(STDOUT, InterpGrid.name.name) InterpGrid --Tim On Sunday, January 04, 2015 03:36:35 PM Tomas Lycken wrote: > Display of types seems to have changed recently: > > > module Foo > export Bar > type Bar end > end > > using Foo > println(Bar) > > prints "Foo.Bar" although I'm quite sure that until recently it only > printed "Bar". I'm sure there are lots of scenarios where this is very > useful (error reporting, for example), but I have a use case where it's > not. Is there any way to print the *unqualified* type name? > > // Tomas
