Yes, actually. If you're on a 64 bit machine, then the integer literal "0" is an Int64. So int64(0) - 0x12345678 promotes and does the subtraction in Int64. -0x12345678 wraps around to the unsigned integer 0xedcba988 which is greater than typemax(Int32). So the value is too large to represent as a signed Int32.
On Monday, January 5, 2015 5:43:20 PM UTC-8, Chi-wei Wang wrote: > > > > julia version 0.4.0-dev+2496 > > Program: > println(-0x12345678) > println(0-0x12345678) > println(int32(0-0x12345678)) > println(int32(-0x12345678)) > > > Output: > 3989547400 > -305419896 > -305419896 > ERROR: InexactError() > in include at ./boot.jl:248 > in include_from_node1 at loading.jl:128 > in process_options at ./client.jl:312 > in _start at ./client.jl:393 > while loading /home/jack/julia/jia32/test.jl, in expression starting on > line 4 > > > Can this be right? >
