Desperately trying to understand this stuff :-) Would something like @f2() below work here?
Also works in Julia-0.3. Can’t figure it out using staged functions (yet?). Rob J. Goedman [email protected] julia> A = (1, 2, 5) (1,2,5) julia> macro f1(a,b,c) return :($a+$b+$c) end julia> @show @f1(2,4,6); @f1 2 4 6 = 12 julia> julia> B = (3, 6) (3,6) julia> macro f2(a, b) return :($a + sum($b)) end julia> @show @f2(5, B); @f2 5 B = 14 julia> @show @f2(3, B); @f2 3 B = 12 julia> versioninfo() Julia Version 0.4.0-dev+2686 Commit 1548d62* (2015-01-08 15:32 UTC) Platform Info: System: Darwin (x86_64-apple-darwin14.1.0) CPU: Intel(R) Core(TM) i7-3720QM CPU @ 2.60GHz WORD_SIZE: 64 BLAS: libopenblas (USE64BITINT DYNAMIC_ARCH NO_AFFINITY Sandybridge) LAPACK: libopenblas LIBM: libopenlibm LLVM: libLLVM-3.3 > On Jan 7, 2015, at 8:25 PM, Chi-wei Wang <[email protected]> wrote: > > Any ways to achieve this? > > Jameson於 2015年1月7日星期三UTC-8下午7時32分59秒寫道： > the declaration `const A = (2,3)` is not part of the macro environment. > values are only seen by functions. whereas macros only see the surface > syntax. so the arguments to `@f` are the literals `1` and `:(A...)` > > On Wed Jan 07 2015 at 10:04:26 PM Chi-wei Wang <[email protected] > <javascript:>> wrote: > Can ... be applied on macro? I tried this but it didn't compile. > macro f(a,b,c) > return :($a+$b+$c) > end > const A = (2,3) > @f(1, A...) > > > > Chi-wei Wang於 2015年1月7日星期三UTC-8下午6時45分14秒寫道： > It works! I missed the varargs section in the doc. Thanks! > > Greg Plowman於 2015年1月7日星期三UTC-8下午5時26分02秒寫道： > > Would the following work? > > const A = (1,2,3) > f(x::Int, y::Int, z::Int) = x+y+z > f(A...) > > > http://docs.julialang.org/en/release-0.3/manual/functions/#varargs-functions > <http://docs.julialang.org/en/release-0.3/manual/functions/#varargs-functions> > > > On Thursday, January 8, 2015 11:14:23 AM UTC+11, Chi-wei Wang wrote: > Hi, everyone. I am trying to achieve the effect like the following C code: > > #define A 1,2,3 > void f(int x, int y, int z) { > } > > f(A); > > Yet the macro in Julia always returns a single expression. Is it possible to > do this?
