There are plans, to integrate this as an default constructor:
https://github.com/JuliaLang/julia/issues/5333
Best is to write the constructor yourself, to have the correct defaults ;)
By the way, your type is not designed very well, as you're using abstract
field types.
Better would be:
type Parameters{RealT <: Real, RangeT <: FloatRange}
sigma::RealT
xi::RealT
eta::RealT
beta::RealT
rho::RealT
agrid::RangeT
end
see: http://julia.readthedocs.org/en/latest/manual/performance-tips/
=> Avoid containers with abstract type parameters
Am Samstag, 17. Januar 2015 01:34:19 UTC+1 schrieb Andrew:
>
> Suppose I have a model which contains many parameters. I'd like to store
> my parameters in a type, for example
>
> type Parameters
> sigma::Real
> xi::Real
> eta::Real
> beta::Real
> rho::Real
> agrid::FloatRange
> end
>
>
> and then I need to assign some values to my parameters. The natural way I
> see to do this is
>
> params = Parameters(1,2,3,4,5,linrange(1,10,10))
>
>
>
> or something like that. However, the fact that I need to remember the
> order in which I defined these parameters means there is some chance of
> error. In reality I have about 20 parameters, so defining them this way
> would be quite annoying.
>
> It would be nice if there was a constructor that would let me use keyword
> arguments, as in
>
> params = Parameters(sigma=1,xi=2,eta=3,beta=4,rho=5,agrid=linrange(1,10,10
> )) .
>
>
>
> I know I could write my own constructor and use keyword arguments, but
> then I think I'd still need to use the ordered constructor to write that
> one.
>
> Is there an easy way to do this? Maybe a macro that could automatically
> define a constructor with keyword arguments?(I don't know much about
> metaprogramming). Alternatively, is there is a cleaner way to store
> parameters that doesn't use types?
>
> ---
> I did find a related post here.
> https://groups.google.com/forum/#!searchin/julia-users/constructor$20keyword$20arguments/julia-users/xslxrihfO30/jV2awP5tbpEJ
>
> . Someone suggests that you can define a constructor like,
> Foo(;bar=1, baz=2) = new(bar, baz)
>
> which does what I want. Is there a way to macro that so that it's
> automatically defined for every field in the type?
>
