Hi! I get this example to show what I want to do.
function testit()
e=2
function()
e = e+2
e
end
end
testit() return anonymous function
func = testit()
Each time, we run func(), e+2.
func()
4
func()
6
func()
8
It shows that func() can keep a value of e, after testit() is evaluated.
run:
func.env
(Box(8),)
There seems to be an enviroment for this anonymous function.
We can also try
type tmptype
func1::Function
func2::Function
end
function testit2()
e=2
_func1 = function()
e = e+2
e
end
_func2 = function()
e = e+2
e
end
tmptype(_func1,_func2)
end
run:
double_func = testit2()
The value of double_func.func1.env and double_func.func2.env will be
synchronized.
run:
double_func.func1()
It will change the value of double_func.func2.env too.
Finally, here is my question.
It is there any way to change the value of the special `e` without
evaluating double_func.func1() or double_func.func2(), and keep double_func.
func1.env and double_func.func2.env synchronized.
Is there any way to get a reference of the special `e`, bind it to a name
in Main, and change the value in the Box(). It let us change `e` in func2.env
and func1.env, without running double_func.func2()
Why this value get a Box().
Thanks!
