I came up with this, so far
*function compute_hermite_polynomial(n) P = Poly([1]) const x =
Poly([0;
1])
for i = 1:n P = 2x*P - polyder(P) end Pend*
On Monday, February 2, 2015 at 5:24:21 PM UTC+1, Andrei Berceanu wrote:
>
> Andras, no worries :) Now I understand why I couldn't find the polynomials
> in your gist!
>
> //A
>
> On Monday, February 2, 2015 at 5:19:49 PM UTC+1, Andras Niedermayer wrote:
>>
>> Sorry, I meant Cubic Hermite Interpolation. Now I see you're looking for
>> Hermite polynomials.
>>
>> On Monday, February 2, 2015 at 4:50:00 PM UTC+1, Andras Niedermayer wrote:
>>>
>>> I was looking for Hermite polynomials and haven't found any code. I have
>>> some (very unpolished) code.
>>>
>>> I haven't made a public package yet, since it needs to be improved
>>> (especially in terms of efficiency, also documentation). Unfortunately, I'm
>>> unlikely to have time for this in the near future, so I'll just post a link
>>> to a gist:
>>> https://gist.github.com/afniedermayer/57873094430e8ddb201c
>>>
>>> I mainly used it with the output of the ODE.jl.
>>>
>>> I hope this is a useful starting point...
>>>
>>> Best,
>>> Andras
>>>
>>> On Monday, February 2, 2015 at 4:38:57 PM UTC+1, Andrei Berceanu wrote:
>>>>
>>>> Yes, exactly, in order to generate plots like
>>>> http://en.wikipedia.org/wiki/Hermite_polynomials#mediaviewer/File:Hermite_poly_phys.svg
>>>>
>>>> //A
>>>>
>>>> On Monday, February 2, 2015 at 4:36:55 PM UTC+1, Jiahao Chen wrote:
>>>>>
>>>>>
>>>>> > Is there an easy way to compute Hn(x)?
>>>>>
>>>>> Do you mean to evaluate a given Hermite polynomial of order n at a
>>>>> value x?
>>>>>
>>>>
