ok, it is jumping average :)
Nice way, thx, but unfortunatly lenght of my vecotrs are random, 100 it was
only like sample.
reshape of vector length on 256845 is imposible:)
Paul
W dniu wtorek, 10 lutego 2015 11:18:55 UTC+1 użytkownik Gunnar Farnebäck
napisał:
>
> If speed is what's important you almost certainly want some kind of loop.
>
> If it's more important not to have a loop you can satisfy your
> specification with
>
> b = reshape(repmat(mean(reshape(a,10,10),1),10),100)
>
> although that's not what I would call a moving average.
>
> Den tisdag 10 februari 2015 kl. 10:00:36 UTC+1 skrev paul analyst:
>>
>> How to quickly count the moving average with one vector and save the other
>> vector?
>> I have vec a and need to fill vec b moving average of a, in this same range.
>> Is posible to do it whitout while ?
>>
>> julia> a=rand(100);
>> julia> b=zeros(100);
>>
>> julia> b[1:10]=mean(a[1:10])
>> 0.6312220153427996
>>
>> julia> b[11:20]=mean(a[11:20])
>> 0.6356771620528772
>>
>> julia> b
>> 100-element Array{Float64,1}:
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.631222
>> 0.635677
>> 0.635677
>> 0.635677
>> 0.635677
>> 0.635677
>> 0.635677
>> 0.635677
>> 0.635677
>> 0.635677
>> ?
>> 0.0
>>
>>
>> Paul
>> 0.0
>>
>
