El miércoles, 18 de febrero de 2015, 15:58:13 (UTC-6), Kevin Squire
escribió:
>
> Hi Sam,
>
> Just to be clear, you're using PyPlot.jl in Julia, right? The way you
> wrote the code above doesn't actually run in Julia ("base" is "Base" and
> "plt" is "PyPlot"--did you alias those?), and I want to make sure that
> you're not doing something like, e.g., using Python and loading pyjulia.
>
Actually, the Julia `PyPlot` package automatically provides an alias `plt`
for closer compatibility with how `matplotlib` is typically used in Python.
David.
>
> Anyway, assuming that's true...
>
> It's unfortunate that the help is overwritten (might be worth opening an
> issue in PyPlot.jl), but in fact, the version in Base is still working just
> fine. In fact, I don't see a way to call the version in PyPlot without
> using "PyPlot.hist":
>
> julia> using PyPlot
> Warning: Method definition eltype(Any,) in module Base at
> abstractarray.jl:10 overwritten in module Compat at
> /Users/kevin/.julia/v0.3/Compat/src/Compat.jl:163.
> INFO: Loading help data...
>
> julia> hist
> hist (generic function with 6 methods)
>
> julia> hist(rand(1:10, 100)) #calls the Base version
> (0.0:2.0:10.0,[18,14,21,18,29])
>
> julia> @which hist(rand(1:10, 100))
> hist(v::AbstractArray{T,1}) at statistics.jl:599
>
> julia> @which PyPlot.hist(rand(1:10, 100))
> hist(args...) at /Users/kevin/.julia/v0.3/PyPlot/src/PyPlot.jl:367
>
> Cheers,
> Kevin
>
>
> On Wed, Feb 18, 2015 at 10:47 AM, <[email protected] <javascript:>>
> wrote:
>
>> Hi,
>>
>> Once I've loaded pyplot, I can't figure out how to use the base.hist
>> function. What is the workaround?
>>
>> help(base.hist) returns the plt.hist functionality.
>>
>
>
