Didn't know that--thanks for the info!
On Thursday, February 19, 2015, David P. Sanders <[email protected]>
wrote:
>
>
> El miércoles, 18 de febrero de 2015, 15:58:13 (UTC-6), Kevin Squire
> escribió:
>>
>> Hi Sam,
>>
>> Just to be clear, you're using PyPlot.jl in Julia, right? The way you
>> wrote the code above doesn't actually run in Julia ("base" is "Base" and
>> "plt" is "PyPlot"--did you alias those?), and I want to make sure that
>> you're not doing something like, e.g., using Python and loading pyjulia.
>>
>
> Actually, the Julia `PyPlot` package automatically provides an alias `plt`
> for closer compatibility with how `matplotlib` is typically used in Python.
>
> David.
>
>
>>
>> Anyway, assuming that's true...
>>
>> It's unfortunate that the help is overwritten (might be worth opening an
>> issue in PyPlot.jl), but in fact, the version in Base is still working just
>> fine. In fact, I don't see a way to call the version in PyPlot without
>> using "PyPlot.hist":
>>
>> julia> using PyPlot
>> Warning: Method definition eltype(Any,) in module Base at
>> abstractarray.jl:10 overwritten in module Compat at
>> /Users/kevin/.julia/v0.3/Compat/src/Compat.jl:163.
>> INFO: Loading help data...
>>
>> julia> hist
>> hist (generic function with 6 methods)
>>
>> julia> hist(rand(1:10, 100)) #calls the Base version
>> (0.0:2.0:10.0,[18,14,21,18,29])
>>
>> julia> @which hist(rand(1:10, 100))
>> hist(v::AbstractArray{T,1}) at statistics.jl:599
>>
>> julia> @which PyPlot.hist(rand(1:10, 100))
>> hist(args...) at /Users/kevin/.julia/v0.3/PyPlot/src/PyPlot.jl:367
>>
>> Cheers,
>> Kevin
>>
>>
>> On Wed, Feb 18, 2015 at 10:47 AM, <[email protected]> wrote:
>>
>>> Hi,
>>>
>>> Once I've loaded pyplot, I can't figure out how to use the base.hist
>>> function. What is the workaround?
>>>
>>> help(base.hist) returns the plt.hist functionality.
>>>
>>
>>
