Let's say I want to define a type that contains a Function type: type IterFunc iter_trigger::Int64 func::Function end
Is there any way to say that the func member in that type should be a
function that takes arguments of a certain type?
Something like (not valid syntax, I tried):
type IterFunc
iter_trigger::Int64
func::Function{i::Int64, something::SomeType}
end
?
