Baz shows up then. From OS X:
julia> t = @async (println("foo");println("bar"); println("baz"));
foo
julia> bar
julia> baz
_
On Tue, Mar 10, 2015 at 9:28 PM, Amit Murthy <[email protected]> wrote:
> What about if you don't print t .
>
> t = @async (println("foo");println("bar"); println("baz"));
>
> On Wed, Mar 11, 2015 at 9:31 AM, Sam L <[email protected]> wrote:
>
>> Same thing on arch linux actually:
>>
>> | | |_| | | | (_| | | Version 0.3.7-pre+15 (2015-03-02 23:43 UTC)
>> _/ |\__'_|_|_|\__'_| | Commit 0f0b136 (8 days old release-0.3)
>> |__/ | x86_64-unknown-linux-gnu
>>
>> julia> t = @async (println("foo");println("bar"); println("baz"))
>> foo
>> Task (queued) @0x0000000003c57080bar
>>
>>
>> julia>
>> _
>>
>>
>>
>> On Tuesday, March 10, 2015 at 8:59:52 PM UTC-7, Sam L wrote:
>>>
>>> I see the behavior on OS X. It also occurs with three println's.
>>>
>>> | | |_| | | | (_| | | Version 0.3.7-pre+1 (2015-02-17 22:12 UTC)
>>> _/ |\__'_|_|_|\__'_| | Commit d15f183* (21 days old release-0.3)
>>> |__/ | x86_64-apple-darwin13.4.0
>>>
>>> julia> t = @async (println("foo");println("bar"); println("baz"))
>>> foo
>>> Task (queued) @0x00007fa0faf0e520bar
>>>
>>>
>>> julia>
>>> _
>>>
>>> The _ indicates the cursor position after running the line of code. I
>>> hit return only once after the first line starting with 't = @async...',
>>> and I got two blank lines after Task was displayed, before the julia>
>>> prompt, and the cursor ended up in the first column on a new line after the
>>> julia> prompt.
>>>
>>>
>>> On Tuesday, March 10, 2015 at 8:17:30 PM UTC-7, Amit Murthy wrote:
>>>>
>>>> Works fine on Linux.
>>>>
>>>>
>>>>
>>>> On Tue, Mar 10, 2015 at 11:28 PM, Ben Arthur <[email protected]>
>>>> wrote:
>>>>
>>>>> in my continuing quest to understand Julia tasks, i have created the
>>>>> following contrived example which does not behave as i would expect. can
>>>>> anyone help explain please? thanks in advance.
>>>>>
>>>>> julia> function printfoobar()
>>>>> println("foo")
>>>>> println("bar")
>>>>> end
>>>>>
>>>>> printfoobar (generic function with 1 method)
>>>>>
>>>>> julia> printfoobar() # great, it works
>>>>> foo
>>>>> bar
>>>>>
>>>>> julia> println("honey"); println("wagon") # no surprise again
>>>>> honey
>>>>> wagon
>>>>>
>>>>> julia> t = @async (println("honey"); println("wagon")) # works too,
>>>>> modulo 'Task' being inbetween
>>>>> honey
>>>>> Task (queued) @0x00007fb59e832500wagon
>>>>>
>>>>> julia> t = @async printfoobar() # ditto: foo and bar both printed,
>>>>> albeit with 'Task' inbetween
>>>>> foo
>>>>> Task (queued) @0x00007fb59f2e1720bar
>>>>>
>>>>> julia> t = @async (println("honey"); printfoobar(); println("wagon"))
>>>>> # WHERE ARE bar AND wagon ???
>>>>> honey
>>>>> Task (queued) @0x00007fb59f2e1840foo
>>>>>
>>>>> julia> # <ENTER> #nope, they still don't appear
>>>>>
>>>>> julia> # <ENTER>
>>>>>
>>>>> julia> # <ENTER>
>>>>>
>>>>> julia> wait(t) # nope, still no further printed output
>>>>>
>>>>> julia> yield() # still no joy
>>>>>
>>>>> julia> istaskdone(t)
>>>>> true
>>>>>
>>>>> is it that println("foo") and println("wagon") never get executed? or
>>>>> that the output stream is just not making it to the REPL? this is in
>>>>> 0.3.6
>>>>> by the way. similar things happen on a 0 day old master.
>>>>>
>>>>
>>>>
>
