Hi
Thanks Mauro for the advice - all makes sense now.
Regards
On Thursday, 12 March 2015 11:28:22 UTC, Mauro wrote:
>
> > Hi
> > Mauro - thanks for that as that makes it clear whats happening under the
> > bonnet. So, what if you then wanted to sum...
> > 1.4827
> > 1.48069
> > 0.884897
> > 1.22739
> > .... is that possible or am I being a bit dumb here.
>
> Just add another sum(ans) after below two statements, that then sums the
> >> 4-element Array{Float64,1}:
> >> 1.4827
> >> 1.48069
> >> 0.884897
> >> 1.22739
>
> > On Thursday, 12 March 2015 10:59:34 UTC, Mauro wrote:
> >>
> >> > Can I still sum?
> >>
> >>
> >> Maybe it's clearer like this:
> >> julia> [ x[i-4:i-1] for i = [6,7,8]]
> >> 3-element Array{Array{Float64,1},1}:
> >> [0.392471,0.775959,0.314272,0.390463]
> >> [0.775959,0.314272,0.390463,0.180162]
> >> [0.314272,0.390463,0.180162,0.656762]
> >>
> >> julia> sum(ans)
> >> 4-element Array{Float64,1}:
> >> 1.4827
> >> 1.48069
> >> 0.884897
> >> 1.22739
> >>
> >> So 1.4827 = ans[1][1]+ans[2][1]+ans[3][1]
> >>
> >> > On Thursday, 12 March 2015 09:50:19 UTC, Mauro wrote:
> >> >>
> >> >> > const x = rand(8)
> >> >> > [ x[i-4:i-1] for i = 6] .. this gives me a 4 element array.
> >> >>
> >> >> This seems a bit odd, what are you trying to achieve here? Anyway
> it
> >> >> produces a Array{Array{Float64,1},1}, i.e. an array of arrays
> >> containing
> >> >> one array.
> >> >>
> >> >> > I now want to sum the ouput - this is what I tried ...
> >> >> > sum([ x[i-4:i-1] for i = 6]) ... what am I doing wrong?
> >> >>
> >> >> This sums all first elements, second elements, etc. As there is
> only
> >> on
> >> >> array in the array, it doesn't do all that much.
> >> >>
> >>
> >>
>
>
