Thank you all for the explanation! We don't stop learning in this list! Best,
Charles On Thu, Mar 12, 2015 at 3:10 PM, Tamas Papp <[email protected]> wrote: > > On Thu, Mar 12 2015, Ivar Nesje wrote: > > >> > >> So, what you would want to do is `Array{String,1}()`. > >> That ought to construct a array of strings with dimension 1 but doesn't. > > > > > > But in 0.4 you can use Array{String,1}(0) to create a 1d array with 0 > > elements. Note that you have to provide the size of the array, and 0 is > not > > default (, but maybe it should be?) > > Array{T}(dims...) > > is equivalent to > > Array{T,length(dims)}(dims...) > > while the latter has a redundant parameter. So instead of providing a > default for dims..., wouldn't > > Array{T}(0) > > be an idiomatic solution for creating an empty vector of eltype T? Has > one less character than > > Array{T,1}(0) > > :D > > Best, > > Tamas > -- Um axé! :) -- Charles Novaes de Santana, PhD http://www.imedea.uib-csic.es/~charles
