Doesn't using the following package solves this issue?
https://github.com/lindahua/Formatting.jl
On Monday, March 23, 2015 at 2:07:11 PM UTC+1, Milan Bouchet-Valat wrote:
>
> Le lundi 23 mars 2015 à 05:50 -0700, Daniel Carrera a écrit :
> > Dear all,
> >
> >
> > For me personally my biggest irritation with Julia is the fact that
> > @sprintf() is a macro and not a function. That means that I am always
> > forced to write the entire format string in one go. For example, this
> > doesn't work:
> >
> >
> > julia> fmt = "%3d"
> > "%3d"
> >
> >
> > julia> @sprintf(fmt,a)
> > ERROR: @sprintf: first argument must be a format string
> >
> >
> >
> >
> >
> > If the format string is long, or if I want to generate it dynamically,
> > this quickly becomes cumbersome and irritating. I would much rather
> > have a traditional printf() and sprintf() function that I can use
> > naturally:
> >
> >
> > fmt = "%15s - " * repeat(" %7.4f", 17)
> >
> >
> > printf(fmt * "\n", name, vals...)
> >
> >
> >
> >
> > Yes, it is possible to work around this seemingly arbitrary
> > limitation, but that goes against the spirit of writing code that is
> > clear and simple. I generally like Julia because the code is clear
> > with very little extraneous syntax, so the implementation of @sprintf
> > sticks out like a sore thumb.
> >
> >
> > Is there any hope that this might change some day? I really don't
> > understand why we have to use a macro here. Even C/C++ can manage to
> > have a printf function. Why can't Julia?
> There was a discussion about this recently, but it stopped prematurely:
> https://github.com/JuliaLang/julia/pull/9243
>
>
> Regards
>
>
