Thank you for the code and the pull request link. Very interesting.

On Tuesday, April 7, 2015 at 8:55:34 PM UTC+2, Mauro wrote:
>
> In 0.3 it's not possible in 0.4 this works: 
>
> julia> type A{T,P} 
>            a::T 
>        end 
>
> julia> typealias B{T} A{T, 1} 
> A{T,1} 
>
> julia> call{T}(::Type{B}, a::T) = B{T}(a) 
> call (generic function with 936 methods) 
>
> julia> B(1.0) 
> A{Float64,1}(1.0) 
>
> See https://github.com/JuliaLang/julia/pull/8712 for discussion 
> call-overloading. 
>
> On Tue, 2015-04-07 at 20:26, Kristoffer Carlsson <[email protected] 
> <javascript:>> wrote: 
> > Let's say I have a type parameterized with two other types and I do the 
> > following: 
> > 
> > type A{T,P} 
> >     a::T 
> > end 
> > 
> > typealias B{T} A{T, 1} 
> > 
> > B(1.0) # Error 
> > 
> > B{Float64}(1.0) # Works 
> > 
> > Is there anyway you could write the code so that the T type is inferred 
> > from the argument to the call to B. 
> > 
> > Best regards, 
> > Kristoffer Carlsson 
>
>

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