Hi,
I am trying to write something analogous to
COMMON-LISP:WITH-OUTPUT-TO-STRING, what I have so far is
macro with_output_to_string(stream, expr)
quote
let $(esc(stream)) = IOBuffer()
$expr
takebuf_string($(esc(stream)))
end
end
end
Works fine:
@with_output_to_string io begin
println(io, "testing")
@printf(io, "pi is %.5f", Float64(pi))
end
but I have a couple of questions:
1. Is there a way I can get rid of the `begin`? Julia syntax for
built-ins that have implicit blocks (`for`, `function`) has no `begin`,
is it possible to write a macro in a similar style? Ie is there
something analogous to COMMON-LISP:&BODY in Julia? (in effect, not in
syntax, I know about varargs, but they don't look right here).
2. I thought that if I make the first argument STDOUT, I can get rid of
the stream name in the body, but it doesn't work (still prints to
console). What is the right way?
3. In Common Lisp, it is common for the first argument to be an
s-expression that is then destructured. Is that idiomatic in Julia? Can
you point me to some examples?
Best,
Tamas
