[julia-users] forming an FFT matrix in julia

[Edward Chen]

To whom it may concern:

2 issues:

   1. In MATLAB, we can form an nxn FFT matrix by doing fft(eye(n)). In 
   Julia, doing fft(eye(n)) doesn't seem to be giving me the same result.
   2. I am actually interested in randomly sampling the rows of a FFT 
   matrix, and doing matrix-vector multiples with only those rows. I was 
   wondering if there was a way to use plan_fft to get the nlogn flop speed 
   using plan_fft in this case.


Thanks!
Ed