Re: [julia-users] Re: How to create own format with two digits 3=03, 10=10, 99=99 (only range 00:99)

[Paul Analyst]

This Way now I`am working. I am lookingo for somthing faster.
Paul
W dniu 2015-05-20 o 17:56, Tim Wheeler pisze:

Could you just cast your strings to normal integers, do your arithmetic, and then convert it back to a string with the necessary zero-padding?

```
@sprintf("%02d", int("01")*int("02"))
```

On Wednesday, May 20, 2015 at 8:28:03 AM UTC-7, paul analyst wrote:

    Big thx, but I need:
     01*02=02
    like 1*2=2
    Paul
    W dniu 2015-05-20 o 14:21, Kristoffer Carlsson pisze:

    In Julia you concatenate strings with *

    |
    julia>a=[@sprintf("%02d",i)fori =1:99];


    julia>a[1]*a[2]
    "0102"

    |



    On Wednesday, May 20, 2015 at 10:05:08 AM UTC+2, paul analyst wrote:

        Txh, but unfortunatly is not to compute

        julia> a=[@sprintf("%02d",i) for i = 1:99];

        julia> a[1]+a[2]
        ERROR: MethodError: `+` has no method matching
        +(::ASCIIString, ::ASCIIString)
        Closest candidates are:
          +(::Any, ::Any, ::Any)
          +(::Any, ::Any, ::Any, ::Any...)

        I have in string data with time and i must compute changes
        only in on 2 last position
        table=
        2015-01-01
        2015-01-01
        2015-01-12

        I take last two digits
        int(table[i][9:10])
        compute somthing

        and I must put the last two Chars
        Always i need 2 char '12' or '01'



        Paul



        W dniu 2015-05-20 o 09:57, Jeff Waller pisze:

        |

        *[@sprintf("%02d",i)fori =1:99]*

        |