Not tested, but xsub = sub(x, 10:20) Base.LinAlg.axpy!(a, y, xsub)
should work just fine. --Tim On Saturday, May 30, 2015 02:35:01 PM Gabriel Goh wrote: > Hey All, > > I'm wondering if its easy to do an in place assignment, say > > x[10:20] = x[10:20] + a*y > > using the axpy! library. I want to avoid the use of any temporary variables > if possible! > > Thanks! > Gabe
