I am having problems with using PyPlot in the nightly build (version
0.4.0). Typing 'using PyPlot' followed by 'plot([sin(a) for
a=linspace(0,2*pi)])' yields the following:
_
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_) | Documentation: http://docs.julialang.org
_ _ _| |_ __ _ | Type "help()" for help.
| | | | | | |/ _` | |
| | |_| | | | (_| | | Version 0.4.0-dev+5416 (2015-06-17 00:39 UTC)
_/ |\__'_|_|_|\__'_| | Commit 0bb31a0 (1 day old master)
|__/ | x86_64-w64-mingw32
julia> using PyPlot
Warning: New definition
call(Type{PyCall.PyDict}, Base.Associative{#K<:Any, Any}) at
C:\Users\Linus\.julia\v0.4\PyCall
rc\conversions.jl:464
is ambiguous with:
call(Type{PyCall.PyDict}, Base.Associative{Any, #V<:Any}) at
C:\Users\Linus\.julia\v0.4\PyCall
rc\conversions.jl:463.
To fix, define
call(Type{PyCall.PyDict}, Base.Associative{Any, Any})
before the new definition.
WARNING: No working GUI backend found for matplotlib.
C:\Anaconda\lib\site-packages\matplotlib\__init__.py:1318: UserWarning:
This call to matplotlib.u
() has no effect
because the backend has already been chosen;
matplotlib.use() must be called *before* pylab, matplotlib.pyplot,
or matplotlib.backends is imported for the first time.
warnings.warn(_use_error_msg)
WARNING: ntuple(n::Integer,f::Function) is deprecated, use ntuple(f,n)
instead.
in depwarn at deprecated.jl:62
in ntuple at deprecated.jl:49
in convert at C:\Users\Linus\.julia\v0.4\PyCall\src\conversions.jl:222
in py2array at C:\Users\Linus\.julia\v0.4\PyCall\src\conversions.jl:73
in convert at C:\Users\Linus\.julia\v0.4\PyCall\src\conversions.jl:429
in pywrap at C:\Users\Linus\.julia\v0.4\PyCall\src\PyCall.jl:305
in pywrap at C:\Users\Linus\.julia\v0.4\PyCall\src\PyCall.jl:304
in __init__ at C:\Users\Linus\.julia\v0.4\PyPlot\src\PyPlot.jl:149
in include at boot.jl:254
in include_from_node1 at loading.jl:133
in reload_path at loading.jl:157
in _require at loading.jl:69
in require at loading.jl:52
while loading C:\Users\Linus\.julia\v0.4\PyPlot\src\PyPlot.jl, in
expression starting on line 560
julia> plot([sin(a) for a=linspace(0,2*pi)])
WARNING: ntuple(n::Integer,f::Function) is deprecated, use ntuple(f,n)
instead.
in depwarn at deprecated.jl:62
in ntuple at deprecated.jl:49
in convert at C:\Users\Linus\.julia\v0.4\PyCall\src\conversions.jl:222
in convert at C:\Users\Linus\.julia\v0.4\PyCall\src\conversions.jl:846
in jl_Function_call at C:\Users\Linus\.julia\v0.4\PyCall\src\callback.jl:36
in pycall at C:\Users\Linus\.julia\v0.4\PyCall\src\PyCall.jl:73
in plot at C:\Users\Linus\.julia\v0.4\PyPlot\src\PyPlot.jl:371
in anonymous at no file
while loading no file, in expression starting on line 0
1-element Array{Any,1}:
PyObject <matplotlib.lines.Line2D object at 0x000000001555D080>
julia> plot([sin(a) for a=linspace(0,2*pi)])
1-element Array{Any,1}:
PyObject <matplotlib.lines.Line2D object at 0x000000001555D2B0>
As you can see importing PyPlot produces several warnings, one of them is
'WARNING:
No working GUI backend found for matplotlib' which led me to believe there
is a problem with loading matplotlib? I am using python 2.7.9 on windows
8.1 with the Anaconda 2.2.0 distribution and matplotlib version 1.4.3.
The plot function returns a PyObject properly but no plot window is opened.
In Julia 0.3.9 everything works as you would expect with no warnings.
Any ideas?
