Not sure if this is what you're looking for, but if you have a generic
function, you can (kind of) pluck out the body of the specified method as
follows:
julia> f(x::Int) = x+5
f (generic function with 1 method)
julia> e = code_typed(f, (Int,))
1-element Array{Any,1}:
:($(Expr(:lambda, Any[:x], Any[Any[Any[:x,Int64,0]],Any[],Any[],Any[]], :(
begin # none, line 1:
return (top(box))(Int64,(top(add_int))(x::Int64,5))
end::Int64))))
julia> dump(e)
Array(Any,(1,))
1: Expr
head: Symbol lambda
args: Array(Any,(3,))
1: Array(Any,(1,))
1: Symbol x
2: Array(Any,(4,))
1: Array(Any,(1,))
1: Array(Any,(3,))
2: Array(Any,(0,))
3: Array(Any,(0,))
4: Array(Any,(0,))
3: Expr
head: Symbol body
args: Array(Any,(2,))
1: Expr
2: Expr
typ: Int64
typ: Any
julia> f_body = e[1].args[3]
:(begin # none, line 1:
return (top(box))(Int64,(top(add_int))(x::Int64,5))
end::Int64)
f_body can then be inspected, though clearly it contains more than what it
started with. It will act as the body of a function when eval'd, though I'm
sure this is *not* the best way to achieve such a result:
julia> x = 5
5
julia> eval(f_body)
10
See http://docs.julialang.org/en/latest/manual/metaprogramming/.
Note also the above doesn't work on anonymous functions. Actually, if
somebody *does* know how to inspect code from an anonymous function without
going so deep as the `code` field, I would really love to hear it.
On Sunday, June 21, 2015 at 1:31:22 AM UTC-4, Jiyin Yiyong wrote:
>
> As described in http://blog.leahhanson.us/julia-introspects.html Julia
> parses code to AST.
> But is there function provided to generate code back?
>
> I checked on Google and the docs, but found nothing so far.
> http://docs.julialang.org/en/release-0.3/stdlib/base/
>
>
