You could do also try this, which does not introduce any overhead:
reinterpret(Int, tuple_array, (3, 1000))
But it only works with Julia 0.4 and I'm not sure if you would consider it
as "clean".
Am Montag, 6. Juli 2015 16:10:01 UTC-4 schrieb Júlio Hoffimann:
>
> Hi,
>
> How to convert:
>
> 1000-element Array{Tuple{Integer,Integer,Integer},1}:
> (10,2,1)
> (5,7,10)
> (5,7,4)
> (1,1,6)
> (2,3,6)
> (8,6,4)
> (10,2,4)
> (1,3,9)
> (9,3,7)
> (5,2,4)
> ⋮
> (1,6,8)
> (4,6,6)
> (3,9,5)
> (10,4,10)
> (8,7,4)
> (4,8,9)
> (2,6,10)
> (3,6,5)
> (1,7,10)
>
> into the corresponding 1000x3 matrix in a "clean fashion"?
>
> -Júlio
>
