Maybe
A2 = map( (x)->convert(ASCIIString,x), A)
and then
f = Bool[contains("b",i) for i in A2]
or
f = Bool[contains("b",convert(ASCIIString,i) for i in A]
....Strings are not my speciality :0)
On Wednesday, July 8, 2015 at 3:26:42 PM UTC-3, paul analyst wrote:
>
> Big Thx , but "b",i in oposit order must like below... i,"b"
>
> But my aray is 2261-element Array{Any,1}: , the trick working only
> with Array{ASCIIString,1}: , How convert Array Any to Array ASCIIString ?
>
> julia> [contains("b",i) for i in A]
> 4-element Array{Any,1}:
> false
> false
> false
> false
>
> julia> A
> 4-element Array{ASCIIString,1}:
> "aaa"
> "aab"
> "aac"
> "aba"
>
>
> julia> [contains(i,"b") for i in A]
> 4-element Array{Any,1}:
> false
> true
> false
> true
>
> W dniu 2015-07-08 o 19:58, Eduardo Lenz pisze:
> > [contains("b",i) for i in A]
>
>
