What version of Julia are you running on?
That worked for me, i.e.
julia> z = [a, "foo", "bar"]
3-element Array{UTF8String,1}:
"foobar⊕"
"foo"
"bar"
julia> map(x->x[end], z)
3-element Array{Char,1}:
'⊕'
'o'
'r'
On Friday, July 17, 2015 at 9:16:27 AM UTC-4, paul analyst wrote:
>
> This
> map(x->x[1:min(length(x),15)], A)
>
> This is ok, but now i must take only last char from any row this array A.
> How do it ?
>
> julia> map(x->x[length(x)],A)
> ERROR: BoundsError()
> in next at utf8.jl:56
> in anonymous at none:1
> in map_to! at abstractarray.jl:1311
> in anonymous at none:1
> in map at abstractarray.jl:1331
>
>
> julia> map(x->x[end],A)
> ERROR: BoundsError()
> in next at utf8.jl:56
> in anonymous at none:1
> in map_to! at abstractarray.jl:1311
> in anonymous at none:1
> in map at abstractarray.jl:1331
> Paul
>
>
> W dniu 2015-07-02 o 21:13, Tom Breloff pisze:
>
> Try:
> map(x->x[1:min(length(x),15)], A)
>
>
>
> On Thursday, July 2, 2015 at 3:06:33 PM UTC-4, paul analyst wrote:
>>
>> How from dimensional array cut out no more than the first 15 characters of
>> each line, without loop. is posible it ?
>>
>> I have :
>> julia> A
>> 3-element Array{Any,1}:
>> "Lorem ipsum dolor sit amet consectetur adipiscing elit sed do eiusmod
>> tempor incididunt ut labore et dolore magn
>> a aliqua. "
>> "Ut enim ad minim veniam quis nostrud exercitation ullamco laboris nisi
>> ut aliquip ex ea commodo consequat. "
>>
>> "Duis aute irure dolor in reprehenderit in voluptate velit esse cillum
>> dolore eu fugiat nulla pariatur. Excepteur
>> sint occaecat cupidatat non proident sunt in culpa qui officia deserunt
>> mollit anim id est laborum."
>>
>> But i need
>>
>> julia> A
>> 3-element Array{Any,1}:
>> "Lorem ipsum dolor
>> a aliqua. "
>> "Ut enim ad minim
>>
>> "Duis aute irure d
>> sint occaecat cupi
>>
>>
>
