calling the following function: workspace()
should clear prior definitions, as well ... best, cdm On Monday, July 27, 2015 at 6:27:17 AM UTC-7, Tom Breloff wrote: > > Your line "g = zz(2,3)" should have failed. I suspect you defined a zz > function earlier in your session and it's dispatching on that. Restart > your julia session to get clean results. > > I think you probably wanted to do: > > z(x,y) = x+y > zz(f::Function, x, y) = f(x,y) > zzz(f::Function, x, y) = zz(f, x, y) > z(2,3) # 5 > zz(z,2,3) # 5 > zzz(z,2,3) #5 > > On Mon, Jul 27, 2015 at 9:18 AM, Joe Tusek <[email protected] > <javascript:>> wrote: > >> I was exploring passing functions to functions and wrote the following >> >> function z(x,y) >> x+y >> end >> >> function zz(z) >> end >> >> g = zz(2,3) # gives a result g = 5 >> >> function zzz(zz) >> end >> >> c = zzz(1,7) #no result, claims that zzz has no methods for two int64 >> arguments. >> >> Why is that? I would expect when g was evaluated it used function z for >> the evaluation of zz and hence, when calling zzz it would be reaching all >> the way back to z? >> >> >> >
