Ahah, thank you both.

On Wednesday, August 12, 2015 at 8:22:09 AM UTC-4, Sisyphuss wrote:
>
> "Tuple types are *covariant* in their constituent types"
>
> Ref: http://docs.julialang.org/en/release-0.3/manual/types/#tuple-types
>
> I think this is for the sake of dispatch.
>
>
>
> On Wednesday, August 12, 2015 at 2:14:14 PM UTC+2, David Gold wrote:
>>
>> @Stefan,
>>
>> I'd have thought that parametric types being invariant in typevars would 
>> lead to 
>>
>>         !(Tuple{ASCIIString, ASCIIString} <: Tuple{String, String})
>>
>> just as
>>
>>         !(Vector{ASCIIString} <: Vector{String})
>>
>> Tuples seem to behave specially?
>>
>> On Tuesday, August 11, 2015 at 4:18:38 PM UTC-4, Stefan Karpinski wrote:
>>>
>>> Same thing – even though
>>>
>>> Tuple{ASCIIString,ASCIIString} <: Tuple{String,String} <: Tuple
>>>
>>>
>>> due to invariance, we still have these:
>>>
>>> !(Vector{Tuple{String,String}} <: Vector{Tuple})
>>>
>>> !(Vector{Tuple{ASCIIString,ASCIIString}} <: Vector{Tuple})
>>> !(Vector{Tuple{ASCIIString,ASCIIString}} <: Vector{Tuple{String,String}
>>> })
>>>
>>>
>>> On Tue, Aug 11, 2015 at 4:13 PM, Seth <[email protected]> wrote:
>>>
>>>> Thanks, Stefan. I understand that causing the problem for baz(), but 
>>>> why does this explain bar()'s failure?
>>>>
>>>> On Tuesday, August 11, 2015 at 1:10:27 PM UTC-7, Stefan Karpinski wrote:
>>>>>
>>>>> Parametric typing in Julia is invariant, so
>>>>>
>>>>> !(Vector{Tuple{ASCIIString,ASCIIString}} <: 
>>>>> Vector{Tuple{String,String}})
>>>>>
>>>>>
>>>>> even though
>>>>>
>>>>> Tuple{ASCIIString,ASCIIString} <: Tuple{String,String}.
>>>>>
>>>>>
>>>>> See: 
>>>>> http://docs.julialang.org/en/release-0.3/manual/types/#parametric-composite-types
>>>>>
>>>>> On Tue, Aug 11, 2015 at 1:26 PM, Seth <[email protected]> wrote:
>>>>>
>>>>>> Consider
>>>>>>
>>>>>> foo(a::Vector) = 1
>>>>>> bar(a::Vector{Tuple}) = 2
>>>>>> baz(a::Vector{Tuple{AbstractString, AbstractString}}) = 3
>>>>>>
>>>>>>
>>>>>> foo(a::AbstractString) = foo([(a,a)])
>>>>>> bar(a::AbstractString) = bar([(a,a)])
>>>>>> baz(a::AbstractString) = baz([(a,a)])
>>>>>>
>>>>>> Results:
>>>>>>
>>>>>> julia> foo("a")
>>>>>> 1
>>>>>>
>>>>>> julia> bar("a")
>>>>>> ERROR: MethodError: `bar` has no method matching 
>>>>>> bar(::Array{Tuple{ASCIIString,ASCIIString},1})
>>>>>>  in bar at none:1
>>>>>>
>>>>>> julia> baz("a")
>>>>>> ERROR: MethodError: `bar` has no method matching 
>>>>>> bar(::Array{Tuple{ASCIIString,ASCIIString},1})
>>>>>>  in baz at none:1
>>>>>>
>>>>>> I understand why foo() works, but why do bar() or baz() both fail?
>>>>>>
>>>>>
>>>>>
>>>

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