SubArrays should let you do this.
julia> x = 1:5
1:5
julia> y = sub(x, 4:8)
5-element SubArray{Int64,1,UnitRange{Int64},(UnitRange{Int64},)}:
4
5
#undef
#undef
#undef
julia> y[0]
3
julia> y[-2]
1
julia> y[2]
5
--Tim
On Tuesday, August 25, 2015 10:57:50 AM Sven Duve wrote:
> Hello,
>
> I am on Julia 0.3.9, I am trying to implement an American Binomial Spread
> Options model. I got it working, but am wondering if there is a different
> solution, perhaps cleaner one.
>
> I am doing the following to populate the options value's array, and then
> loop over the array to simulate the exercise conditions in the tree:
>
>
> for i in range(N-1, -1, N) ## the outer loop is counting down walking
> back in the tree
> for j in range(-i, 2, i+1)
> for k in range(-i, 2, i+1)
>
> C[k+(N+1), j+(N+1)] = "some value" ## so in order to position
> the value to the right location in the Array, I need to adjust the index
> with (N+1)
>
> end
> end
> end
>
>
> The question really is, can I create a matrix and change the indexing like
> A = eye(), so that when A[0, 0] would be the center of the matrix?
>
>
> Thanks
>
>
> Sven
