Many thanks, guys! Indeed reshape(a,length(a)) is much faster than doing in the simplest way. However, it brings another question:
When I ran the command: function myfunc1(corpus) wc = wordcloud(x = corpus[:]) end function myfunc2(corpus) wc = wordcloud(x = reshape(corpus,length(corpus))) end I get the following performance: @time myfunc1(corpus) 1st running: 398.202 milliseconds (452 k allocations: 17406 KB) 2nd running: 144.181 microseconds (374 allocations: 20832 bytes) 3rd running: 99.270 microseconds (374 allocations: 20832 bytes) 4th running: 93.860 microseconds (374 allocations: 20832 bytes) @time myfunc2(corpus) 1st running: 4.102 milliseconds (2667 allocations: 136 KB) 2nd running: 110.182 microseconds (375 allocations: 20464 bytes) 3rd running: 130.949 microseconds (375 allocations: 20464 bytes) 4th running: 120.142 microseconds (375 allocations: 20464 bytes) It is clear that it is much faster and occupies much less memory in the first running. And actually I only need to run it once. However I am curious to know why would myfunc2 be slower than the myfunc1 as the number of running increase? Thanks for everything! Best, Charles On 10 September 2015 at 19:24, Steven G. Johnson <stevenj....@gmail.com> wrote: > > > On Thursday, September 10, 2015 at 10:39:58 AM UTC-4, Seth wrote: >> >> would vec() also work for you? It's supposed to be pretty fast. >> >>> <http://www.imedea.uib-csic.es/~charles> >>> >> > vec(a) is equivalent to reshape(a, length(a)), and is fast because it > doesn't make a copy of the data. > -- Um axé! :) -- Charles Novaes de Santana, PhD http://www.imedea.uib-csic.es/~charles
