Ah.
Maybe [Array(Int64,n) for n in map(k -> binomial(J,k), 1:K)] is what you’re looking for? // T On Monday, September 21, 2015 at 10:18:31 AM UTC+2, Alan Crawford wrote: The lower case k is intentional. I didn't want such a 'large' array as the > one created when I use K because large parts of that array would be > redundant. Ideally, I want this array to be as small as possible, > especially since J and K might be quite a bit larger than in the example. > > On Monday, 21 September 2015 09:13:53 UTC+1, Tomas Lycken wrote: >> >> Are you sure that’s not just a typo between k and K (note the case >> difference)? >> >> This works for me: >> >> J=10 >> K=3 >> MyArray = [Array(Int64,k) for k in 1:K, n in 1:binomial(J,K)] >> >> // T >> >> On Monday, September 21, 2015 at 10:08:13 AM UTC+2, Alan Crawford wrote: >> >> Hi, >>> >>> I'd like to be able to define an array of vectors where the number of >>> vectors in the array is linked to the length of the vector. For example, I >>> want to be define an array with say 10 scalars, 45 length 2 vectors, 120 >>> length 3 vectors, .... and so on. Intuitively, I thought the following code >>> might achieve this: >>> >>> J=10 >>> K=3 >>> MyArray = [Array(Int64,k) for k in 1:K, n in 1:binomial(J,k)] >>> >>> >>> However, it seems i cannot use k to define the number of element indexed >>> by n. >>> >>> I was wondering if anyone knew how to create the desired array? >>> >>> Thanks >>> Alan >>> >> >> >
